- #1
iggybaseball
- 57
- 0
I am having trouble solving this integral:
[tex]\frac{\1}{(4-z^2)^(3/2)}[/tex]
I know that x = asin(theta)
theta = arcsin (x/a)
d(theta) = 1 / sqrt(4-z^2) dz
but then I get stuck. Could someone give me a hand?
ps there should be a number 1 on top of the fraction and the integral has dz after it respectfully. I couldn't get these two in ( It is the first time I used latex) Thanks
[tex]\frac{\1}{(4-z^2)^(3/2)}[/tex]
I know that x = asin(theta)
theta = arcsin (x/a)
d(theta) = 1 / sqrt(4-z^2) dz
but then I get stuck. Could someone give me a hand?
ps there should be a number 1 on top of the fraction and the integral has dz after it respectfully. I couldn't get these two in ( It is the first time I used latex) Thanks