- 57

- 0

[tex]\frac{\1}{(4-z^2)^(3/2)}[/tex]

I know that x = asin(theta)

theta = arcsin (x/a)

d(theta) = 1 / sqrt(4-z^2) dz

but then I get stuck. Could someone give me a hand?

ps there should be a number 1 on top of the fraction and the integral has dz after it respectfully. I couldn't get these two in ( It is the first time I used latex) Thanks