The problem tells you that "I" is the "illumination"- the intensity of the light at that point. However, as tinytim suggests, knowing the specific physical meaning of variables is not necessary to do the mathematics!
recall from elementary trigonometry that
1+cot(t)^2=csc(t)^2
you got a little carried away
you wrote AN=x sin(theta)
also AN=1 so x=csc(theta)=1/sin(theta)
you can write I in terms of theta by substituting x=csc(theta) into I
x^2=x^2cos(theta)^2+x^2sin(theta)^2
reduces to the un helpful
x^2=x^2
not x^2=2x^2+1
#10
rshen5
6
0
Thank you thank you ~~
gee that was easy.. (what was i thinking)
but does anyone know how they actually got the equation? just curious