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## Homework Statement

A model rocket is launched vertically upward. If it's position (height) y above the ground in feet as a function of time t in seconds is given by:

## Homework Equations

y = f(t) = 192t - 16t^2

## The Attempt at a Solution

*1. Find the instantaneous velocity and acceleration at any time t.*

Now this is my first calculus course on my long academic journey, but velocity is the first derivative and acceleration is the second.

Velocity -

y' = 192-32t

That was easy, but it is the second derivative (acceleration) that is stumping me:

y'' = -32

How is that possible.. negative acceleration the entire time?

Thank you for your assistance.