Calorimeter and heat, units question

AI Thread Summary
The discussion revolves around a lab report involving a formula for calculating the specific heat of a metal, expressed as c = (m + M_e)(T_f' - T'_i) / (m(T_c - T_f)). The user is confused about the units, concluding that c appears unitless, while it should have units of cal/g·K. There is a suggestion that the specific heat of the calorimeter metal should be included in the formula, but clarity on this point is lacking. The user references a Spanish website that discusses the same formula, indicating that this confusion is not unique. The conversation highlights the importance of correctly understanding the components and units in calorimetry calculations.
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Homework Statement


I have a lab report due next week and I'm almost done with it. However I'm totally stuck on the last part where it is wrote in a description of the experience : c=\frac{(m+M_e)(T_f'-T'_i)}{m(T_c-T_f)} where c is the specific heat of a metal. If I work out the units in the formula, I end up with c has no units! It must have units of \frac{cal}{g \cdot K}}! But I don't know how to make this appear!
The only thing I imagine that can save me is that the c above is equivalent to one with units, but I don't know how to justify this. Clearly it makes no sense at all to me.
I'd be very grateful if you could help me. (I'd be so glad to finish the report as soon as possible so that I can study vector analysis...)
 
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I think you need a C of the calorimeter metal on the top.
 
mgb_phys said:
I think you need a C of the calorimeter metal on the top.

Sorry I don't understand what you mean.
This formula also appear in some websites, like http://www.sc.ehu.es/sbweb/fisica/estadistica/otros/calorimetro/calorimetro.htm (In Spanish. Where it says
El calor específico desconocido del será por tanto...
)
In my formula M_e is the mass of water to which the calorimeter is equivalent to.
 
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