Calorimeter Constant: Hot/Cold Water - Find & Check

AI Thread Summary
The discussion focuses on calculating the calorimeter constant using the heat transfer data from hot and cold water. The user has calculated the change in enthalpy (delta H) for both warm and cold water, finding values of -5962.6 J for hot water and 5125.45 J for cold water. There is confusion regarding the temperature differences (delta T) and whether they are correctly represented as initial minus final temperatures. Initial temperatures for hot and cold water are provided, along with the final temperature of the mixture, which helps clarify the calculations. The user seeks further guidance on how to proceed with determining the calorimeter constant from this data.
imapeiceofwod
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Hot water:
v- 50ml
delta t = -28.5

Cold water
v=50ml
delta t = 24.5

delta H of warmwater is a 50g(4.184)(-28.5) = -5962.6
delta H of cold water = 5125.45

From there i don't know what to do to find the Calorimeter constant any help? Also i did the above calculations correct right?
 
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Please elaborate on what you did on what you are calculating. What you wrote is hopelessly incomplete.
 
imapeiceofwod said:
I have to determine the calorimeter constant give this data. The hot water is measure and poured into the cold water. I found delta H of the warm and cold water from there I am unsure what i got to do to determine the constant...

Hot water:
v- 50ml
delta T = -28.5 degrees celcius

Cold water
v=50ml
delta T = 24.5 ceclius

delta H =mc delta T
delta H of warmwater is a 50g(4.184)(-28.5) = -5962.6 J
delta H of cold water = 5125.45 J

From there i don't know what to do to find the Calorimeter constant any help? Also i did the above calculations correct right?

fixed, hopefully it more understandable
 
Much better, although I am still not sure about ΔT listed - are these initial minus final respectively? Is 24.5 difference between initial temperature of calorimeter plus 50 mL of cold water and final temperature of everything?
 
Borek said:
Much better, although I am still not sure about ΔT listed - are these initial minus final respectively? Is 24.5 difference between initial temperature of calorimeter plus 50 mL of cold water and final temperature of everything?

here are the initial values.
Temp of hot water = 75 degrees C
temp of cold water 22 degrees C
Final temp of mixture 46.5 C

With those values i determined delta T
 
OK, as I expected, you forgot that you are heating not only cold water.
 
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