Can a Field Player Catch a Baseball Hit at 27 m/s and 32 Degrees?

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A baseball is hit at 27 m/s and 32 degrees, and a field player 50m away needs to determine if he can catch it. The player has a reaction time of 0.5 seconds, which affects his ability to reach the ball. The initial height of the baseball is 1m, and the calculations suggest it takes approximately 2.99 seconds for the ball to reach the player. The required running speed for the player to catch the ball is calculated to be around 7.57 m/s. Understanding the "initial level" refers to the height of the baseball at the time of the hit is crucial for accurate calculations.
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Homework Statement


A baseball is hit at a height of 1m with an initial velocity of 27 m/s at 32 degrees above the horizontal. A field player is located 50m from the home plate along the line of flight.

(a) If he runs, is there a chance he could catch it? what's the velocity?
Assume his reaction time is 0.5s, and that he would catch it at the initial level. MAIN ISSUE: (i don't know what he means by "initial level". initial level of the pitcher, or field player?)

Homework Equations


kinematics equations:
Xf = Xi + ViT + 1/2at^2
Vf^2 = Vi^2 + 2a(delta x)
Vf = Vi + a(delta T)

The Attempt at a Solution


0 = 1 + 14.308T - 4.8T^2
...
T = 2.99s
66.86 = 50 + Vi(2.99s)
...
basically, I got Vi as 7.57m/s instead of 7... maybe it has to do with the "initial position" that i didn't get?
 
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Initial level is simply the height from the ground at which the baseball is hit. Don't forget to take into account the fielder's reaction time.
 
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