Can a Sphere Be Levitated Using Magnets and Rings, Despite Earnshaw's Theorem?

  • Thread starter Thread starter MaJiK9021
  • Start date Start date
  • Tags Tags
    Theorem
AI Thread Summary
Levitation of a sphere using magnets faces challenges due to Earnshaw's theorem, which states that stable levitation cannot be achieved with static magnetic fields. The proposed setup involves a magnetized sphere with repulsive magnetic rings above and below, but this configuration is inherently unstable. Alternative methods like eddy current or diamagnetic levitation are suggested as more feasible options. The discussion also raises questions about the energy requirements for sustained levitation, particularly for heavy loads. Overall, while the idea is intriguing, practical implementation may require different approaches to achieve stability and energy efficiency.
MaJiK9021
Messages
4
Reaction score
0
Hi,

I've been doing some research on an idea of mine, part of which involves levitating a sphere. Apparently Earnshaw's theorem makes this very difficult; but I'm having a hard time imagining why. I'm imagining the sphere as a magnet, with the north pole over the entire outer surface of the sphere and the south pole over the entire inner surface of the sphere. Two magnetic rings circle around the sphere, each parallel to the equator, but one above and one below the equator. These magnetic rings come close to contact with the sphere, but not quite. The rings are oriented so that their north pole is facing the sphere, causing a repulsive force between the rings and the sphere. The rings are held in place by a bar (or whatever) that is attached to both rings and the ground, keeping the rings firmly in place.

With this setup, would the sphere not stably remain levitated within the rings? I'm trying to understand how Earnshaw's theorem would allow this setup to be unstable. Whichever way the sphere moves, it will move towards a repulsive magnet, which will cause it to move back to an equilibrium right in the middle of the rings. Right?
 
Engineering news on Phys.org
You could probably make a magnet like that by having hundreds of cone shaped magnets with the pointy ends magnetized as south poles and all pointing inwards. They would tend to repel each other, of course. Maybe you could glue them together.

Until you got it to be a hemisphere, there would be a return path for the magnetic fields of most of these magnets.
However, as you went beyond a hemisphere, the magnetic fields of the magnets could only return to the other end of the magnet by trying to demagnetise another magnet, so the two magnets would tend to cancel each other out.

When you reached the stage of having a sphere, the net magnetic field outside the magnet would be close to zero.

Nice try, but I don't think it is going to work.
 
MaJiK9021 said:
Hi,

I've been doing some research on an idea of mine, part of which involves levitating a sphere. Apparently Earnshaw's theorem makes this very difficult; but I'm having a hard time imagining why. I'm imagining the sphere as a magnet, with the north pole over the entire outer surface of the sphere and the south pole over the entire inner surface of the sphere. Two magnetic rings circle around the sphere, each parallel to the equator, but one above and one below the equator. These magnetic rings come close to contact with the sphere, but not quite. The rings are oriented so that their north pole is facing the sphere, causing a repulsive force between the rings and the sphere. The rings are held in place by a bar (or whatever) that is attached to both rings and the ground, keeping the rings firmly in place.

With this setup, would the sphere not stably remain levitated within the rings? I'm trying to understand how Earnshaw's theorem would allow this setup to be unstable. Whichever way the sphere moves, it will move towards a repulsive magnet, which will cause it to move back to an equilibrium right in the middle of the rings. Right?

As vk6kro points out, your sphere cannot be magnetized the way you want. Why not just use eddy current levitation? Or diamagnetic material levitation?

http://en.wikipedia.org/wiki/Levitation

.
 
Yes, I suppose eddy current or diamagnetic levitation would work. Which of these would require less energy? I would like to be able to levitate the sphere for a couple hours at a time at least with a load of a couple hundred pounds or so, using a battery. How big of a battery would I need to be able to do this?

I know, the equations to figure all this out on my own are out there somewhere, but I really don't know much about this subject and it would be very helpful if someone could just give me a rough idea if what I'm trying to do is feasible at all. Thanks.
 
Very basic question. Consider a 3-terminal device with terminals say A,B,C. Kirchhoff Current Law (KCL) and Kirchhoff Voltage Law (KVL) establish two relationships between the 3 currents entering the terminals and the 3 terminal's voltage pairs respectively. So we have 2 equations in 6 unknowns. To proceed further we need two more (independent) equations in order to solve the circuit the 3-terminal device is connected to (basically one treats such a device as an unbalanced two-port...
suppose you have two capacitors with a 0.1 Farad value and 12 VDC rating. label these as A and B. label the terminals of each as 1 and 2. you also have a voltmeter with a 40 volt linear range for DC. you also have a 9 volt DC power supply fed by mains. you charge each capacitor to 9 volts with terminal 1 being - (negative) and terminal 2 being + (positive). you connect the voltmeter to terminal A2 and to terminal B1. does it read any voltage? can - of one capacitor discharge + of the...
Hello dear reader, a brief introduction: Some 4 years ago someone started developing health related issues, apparently due to exposure to RF & ELF related frequencies and/or fields (Magnetic). This is currently becoming known as EHS. (Electromagnetic hypersensitivity is a claimed sensitivity to electromagnetic fields, to which adverse symptoms are attributed.) She experiences a deep burning sensation throughout her entire body, leaving her in pain and exhausted after a pulse has occurred...

Similar threads

Back
Top