Can Adding Ice and Steam Change Water Temperature?

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Judy's thermos problem involves calculating the mass of ice needed to achieve a final temperature of 75.0 C from boiling water. The second scenario requires determining the original mass of steam after an ice cube is introduced, resulting in a final temperature of 23 C. The forum emphasizes the importance of showing work for homework help, prompting users to share their thought processes and equations. For the second question, a heat balance equation is suggested, while for the third, a specific heat and latent heat equation is proposed. Overall, the discussion focuses on applying thermodynamic principles to solve heat transfer problems.
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1.) Judy places .150 kg of boiling water in a thermos bottle. How many kilograms of ice at -12.0 C must Judy add to the thermos so that the equilbrium temperature of the water is 75.0 C?

2.) A 0.03 kg ice cube at 0C is placed in an insulated box that contains a fixed quantity of steam at 100 C. When thermal equilibrium of this closed system is established, its temperature is found to be 23C. Determine the original mass of the steam at 100 C.

3.) What will the final temperature if 1 kg of water at 20C is heated by the condensation of 30 g steam at 100 C?
 
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Hi jayphysics,

Forum rules state you must show some work in order to get homework help. What have you tried so far? What equations/concepts do you think you might use? What are you stuck on?
 
Well, for the 2nd question, I think we can use the equation: (Mice)(Lf) + (Mw)(Cw)(Change in Temp) = (Ms)(Lv) + (Msw)(Cw)(Change in Temp) since heat lost will be equal to heat gained. But I am not sure. Is this right?

For the 3rd question, can we use the equation: (Mass of water)(Specific heat capacity of water)(Temp of water) = (mass of steam)(Latent heat of vaporization)

Can anyone help
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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