Can All Coefficients 'a' and 'b' Be Roots in Their Own Set of Quadratics?

  • Thread starter Thread starter app_pp
  • Start date Start date
  • Tags Tags
    Polynomial Root
AI Thread Summary
The discussion revolves around whether all coefficients 'a' and 'b' can serve as roots in a set of 'n' distinct quadratics of the form x^2 + a_ix + b_i. It has been established that this is feasible for n=2, but challenges arise for n greater than 3 due to the lack of fixed positions for each value. The participants note that all values of 'a' and 'b' must be distinct, and both real and complex numbers are considered acceptable roots. Clarification is sought regarding any additional constraints that may apply to the roots. The conversation highlights the complexities involved in extending the solution beyond two quadratics.
app_pp
Messages
3
Reaction score
0
1. Homework Statement :
We have 'n' quadratics is the form x^2 +aix+bi
All values of A and b are different.
Is it possible to have all values of A and B as the roots of the n quadratics

2. The attempt at a solution:
Well. I know that all values of 'a' and 'b' must (if possible) be in one of the n (x-t)(x-s) where t and s are two values of a and/or b. I have proven that when n=2 its possible for all values, however i have difficulty with n>3
 
Physics news on Phys.org
Could you please clarify the question? Are there any other constraints to the question (like the roots must be real/complex)?

Why should there be a problem when n>3?
 
Well there are no other restraints. Only all the values of a and b are different. I assume that both complex and real numbers are possible.

The answer to your second question I was having difficulty with N>3 is because there are not fixed 'positions' for each value
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top