Originally posted by krab
You need the 2nd law to understand what can be done with the heat energy. It tells you that if you want to use the heat rejected by an a/c unit (and that unit is already reasonably efficient), the unit will then be rejecting its heat into a reservoir of slightly higher temperature.
What you have said here is that
the act of using the rejected heat
creates a situation where the unit
is now required to deal with a
higher ambient temp. I do not
understand why you said this. T2
and T3 remain the same whether or
not you harness the difference to
do something else.
This requires the unit to use more energy.
I do not know why you said this.
Using the T3-T2 difference in no
way increases the load on the
unit.
In symbols, let's say the a/c unit is cooling the reservoir at temp. T1, and dumping heat into ambient outside temp. T2. It is also applying work W1. To use some of this heat, the a/c unit will effectively be dumping heat into a reservoir of temp. T3, where T3>T2. To do this, W1 increases to W2.
There is no increase from W1 to
W2 from using T3-T2 to do work.
W1 remains constant and will
happen whether or not you use T3-
T2. The compressor is aleady
required to achieve T3 in
order for the heat removed from
the building to flow "downhill" as
per the second law into the air
outside. Using this "flow" does
not cause the compressor to have
to increase to W2.