Can Anybody Correct My Physics Answers?

  • Thread starter Thread starter freezx
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on correcting physics answers related to kinematics and energy calculations. The participant correctly identifies that when the speed of a moving object is doubled, its kinetic energy increases four times, confirming answer d. In the second question, the participant asserts that two spheres dropped simultaneously have the same acceleration due to gravity, leading to the conclusion that they have the same kinetic energy at a given height. The calculations for work done and potential energy are accurately performed, with the participant demonstrating a solid understanding of the principles involved.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with kinetic and potential energy concepts
  • Knowledge of work-energy principle
  • Basic algebra for solving physics equations
NEXT STEPS
  • Study the principles of gravitational potential energy and kinetic energy conversion
  • Learn about the effects of air resistance on falling objects
  • Explore the work-energy theorem in greater detail
  • Investigate uniform acceleration and its applications in real-world scenarios
USEFUL FOR

Students studying physics, educators teaching kinematics and energy concepts, and anyone preparing for physics examinations or assessments.

freezx
Messages
3
Reaction score
0
Hi
Can anybody correct my answers ?



1- when the speed of a moving object is doubled, its
a- Acceleration is doubled
b- Weight is doubled
c- Kinetic energy is double
d- Kinetic energy is increase four times
My answer is d


2- an iron sphere of mass 40 kg has the same diameter as an aluminium sphere whose mass is 10 kg. the sphere are dropped at the same time from a tower. When they are 115 m from the ground, they have the same:
a- Kinetic energy
b- Potential energy
c- Momentum
d- Impulse
e- Acceleration
My answer is a


3- how much work is done by a force of 10N in moving an object through a distance of 2 m in the direction of the force?
Work= force* distance
= 10 * 2 = 20 J


4- A bag of rice weighs 150 kg. to what height should it be raised so that its potential energy is 10 J ?
PE= mgh
10 = 150 * 9.8 * h
h = 10/(150 * 9.8) = 0.0068 m



5- calculates the work done in lifting 250 kg of water through a vertical height of 8 meters.
PE = mgh
= 250 * 9.8 * 8 = 19600 J
Work = PE
So work = 19600 J


6- A truck weighing 10000N and traveling at 35m/s stops at a distance of 40 m decelerating uniformly. What is the force exerted on it by the brakes? What is the work done by the brakes?
V2 = u2 + 2aS
u2 = -2 aS because the final speed is zero
1225 = - 2 * 40 * a
a = 1225/-80 = -15.31 m/s2
for the time
v = u + at
0 = 35 + (-15.31)* t
- 35 = ( -15.31 ) * t
t = -35/-15.31 = 2.28 s
force = mass * acceleration
10000 = mass * 9.8
mass = 10000/9.8 = 1020.4 kg

force exerted = mass * acceleration
= 1020.4 * - 15.31 = - 15622.32N
work done by the brakes:
work = force * distance
= 10000 * 40 = 400000 Joules
7- A man drops a 15 kg rock from a top of 20 m building. What is its speed just before it hits the ground? What is its kinetic energy when it reaches the ground?
PE= 15 * 9.8 * 20 = 2940 Joules
KE = PE
KE = ½ mv2
2940 = ½ * 15 * v2
2940 = 7.5 * v2
v2 = 2940/7.5
v = square root of ( 2940/7.5)
v = 19.79 m/s
KE= PE
So KE =2940 Joules
 
Physics news on Phys.org
2) I don't think so, Kinetic E.=(1/2)mv^2, don't they different masses? What forcce acts on both of they equally?
 
freezx said:
2- an iron sphere of mass 40 kg has the same diameter as an aluminium sphere whose mass is 10 kg. the sphere are dropped at the same time from a tower. When they are 115 m from the ground, they have the same:
a- Kinetic energy
b- Potential energy
c- Momentum
d- Impulse
e- Acceleration
My answer is a



7- A man drops a 15 kg rock from a top of 20 m building. What is its speed just before it hits the ground? What is its kinetic energy when it reaches the ground?
PE= 15 * 9.8 * 20 = 2940 Joules
KE = PE
KE = ½ mv2
2940 = ½ * 15 * v2
2940 = 7.5 * v2
v2 = 2940/7.5
v = square root of ( 2940/7.5)
v = 19.79 m/s
KE= PE
So KE =2940 Joules

ok,, i think the answer in number 2 should be E,, because the 2 spheres have same diameter,, so same effect of air resistance,, they were dropped at the same time and have same effect of g,, so acceleration is the same...:cool:

i got the same answers on everything but my velocity in number 7 is 19.80m/s
anyway,, the KE i got is the same...

that's all!
 
Problem 2 should state to ignore air resistance, since none of the answers are correct if it is included.
 

Similar threads

Replies
11
Views
3K
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
17
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
5
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
18
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K