- #1

pjgrah01

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## Homework Statement

Prove by contradiction that if b is an integer such that b does not divide k for every natural number k, then b=0.

## Homework Equations

## The Attempt at a Solution

I know that proof by contradiction begins by assuming the false statement: If b is an integer such that b does not divide k for every kεℕ, then b≠0, which is equivalent to "there exists an integer b such that b does not divide k and b≠0, for every kεℕ. But I'm not sure how to proceed from here.