Can Classic Greek Problems Be Solved with Basic Geometry?

  • Thread starter Thread starter gravenewworld
  • Start date Start date
gravenewworld
Messages
1,128
Reaction score
27
I have to give a presentation for geometry, and I chose to do my presentation on the impossiblity of squaring the circle, doubling the volume of a cube, and trisection of an arbitrary angle with Euclidean tools. The problem is though, that I am certain the majority of the class has never been exposed to any field theory at all. Does anyone have any ideas of how I can possibly explain the proofs of why these problems are impossible without having to go to field theory? I mean I will go to field theory if I have to, but then again, no one would understand unless there is a way to easily explain field theory without using heavy duty concepts, like using polynomials etc.
 
Mathematics news on Phys.org
gravenewworld said:
I have to give a presentation for geometry, and I chose to do my presentation on the impossiblity of squaring the circle, doubling the volume of a cube, and trisection of an arbitrary angle with Euclidean tools. The problem is though, that I am certain the majority of the class has never been exposed to any field theory at all. Does anyone have any ideas of how I can possibly explain the proofs of why these problems are impossible without having to go to field theory? I mean I will go to field theory if I have to, but then again, no one would understand unless there is a way to easily explain field theory without using heavy duty concepts, like using polynomials etc.

it looks like that hist of math site has done all your research for you. just look up 1/2 dozen of the references & you're 90% of the way there. all you've got to do is write it up!
 
Thanks a lot for your help. LOL while doing research on these problems, I found this interesting journal article. The legislature in Indiana actually tried to pass legislation in order to change the value of pi first to 4 and then to 3.2 so that the squaring the circle problem could be solved. The legislation actually made it through the House unanimously, but the Senate postponed voting on the bill indefinitely (it can still be voted on today).
 
I pointed this out before, but Archemedies did trisect the angle by using a paper strip.http://www.cut-the-knot.org/pythagoras/archi.shtml

The method is called "illicit," in the article, as if mathematicians were more busy inventing restrictions than solving problems. Quote from above: "It's thus specifically forbidden to use a ruler for the sake of measurement," WHY? Every student has one today.

This also leads to the fact, that in my day, some students believed that they would astonish the mathematical world by trisecting the angle and spent a great deal of time on that. Actually nobody in my high school class understood the difference between a straight edge and a ruler anyway, which was never gone into.
 
Last edited:
There is also a theory of those constructions which allow a marked straight edge (ruler).
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top