Could someone clear up a few things?
Doing the experiment with an atom rather than photons seems important because the atom that makes it to the finish line is supposed to be the same atom that took off at the start, unlike photons... the mean free path for photons in air is a couple of centimeters and each interaction with a mirror is a new emission. The delayed choice experiment using photons is employing a serial sequence of absorbed and freshly emitted new photons along the paths, so the presence or absence of the final mirror seems irrelevant except for the first and subsequent photons created after the choice is made manifest.
The retro-causality appearance seems based on the assumption that the initial photon is the same one that finishes the course... that its state was established at the start and is then mysteriously appropriate for the shifty measurement situation at the end. But seen as a chain of emissions, each new photon gets a "fresh state" based on the measurement situation, right? When the final mirror is placed either in or out, can't the next made photon and all subsequent ones take states as if all the past of the experiment didn't matter and all that was being done was to send a photon to some measurement condition?
So it looks like the trial with the atom is different and important, but the description is not clear. It does seem clear that only one atom was used and this same atom made the whole trip, but the part about the paths is unclear...
"The team then allowed the atom to fall towards crisscrossing laser beams. The lasers split the atom’s trajectory into two possible paths. After the atom passed the crossroads, the equipment randomly switched to a set-up that either recombined the two possible paths, or did not."
What does it mean that the atom's trajectory was split? How was this done?
What does it mean that the two possible paths were either recombined or not? How was this done?
"The atom behaved in the same way as the photon. If the paths were recombined this produced an interference pattern typical of a wave, showing the atom traveled (sic) down two paths at once. If the paths were not recombined, the atom banged into one of the detectors at the end of each track, in the same way a pebble would."
If one atom travels down two paths at once is there twice as much mass present as when it travels down one path?