Can I Represent ln(1+x) as a Power Series?

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Discussion Overview

The discussion centers on the representation of the natural logarithm function ln(1+x) as a power series. Participants explore the equivalence of two proposed power series forms of this function.

Discussion Character

  • Technical explanation, Mathematical reasoning

Main Points Raised

  • One participant presents two forms of the power series for ln(1+x) and asks if they are equivalent.
  • Another participant asserts that the two series are equivalent.
  • A subsequent post provides a mathematical manipulation to show the equivalence of the two series, focusing on the factorial terms involved.
  • Another participant reiterates the equivalence using similar reasoning, emphasizing the simplification of the factorial expressions.

Areas of Agreement / Disagreement

There appears to be agreement among participants that the two power series forms are equivalent, although the discussion does not explore any potential nuances or conditions under which this equivalence holds.

Contextual Notes

The discussion does not address any assumptions or limitations regarding the convergence of the series or the domain of x for which the series representation is valid.

donutmax
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hi!

are the following power series equivalent?

ln(1+x)=[tex]\sum_{n=0}^{\infty} \frac{(-1)^n n! x^{n+1}}{(n+1)!}[/tex]
=[tex]\sum_{n=0}^{\infty} \frac{(-1)^n x^{n+1}}{n+1}[/tex]
 
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Yes.
 
[tex]\frac{(-1)^n n! x^{n+1}}{(n+1)!}=\frac{(-1)^n x^{n+1}}{(n+1)!/n!}=\frac{(-1)^n x^{n+1}}{(n+1)}[/tex]
 
CRGreathouse said:
[tex]\frac{(-1)^n n! x^{n+1}}{(n+1)!}=\frac{(-1)^n x^{n+1}}{(n+1)!/n!}=\frac{(-1)^n x^{n+1}}{(n+1)}[/tex]

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