Can I Represent ln(1+x) as a Power Series?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
3 replies · 9K views
donutmax
Messages
7
Reaction score
0
hi!

are the following power series equivalent?

ln(1+x)=[tex]\sum_{n=0}^{\infty} \frac{(-1)^n n! x^{n+1}}{(n+1)!}[/tex]
=[tex]\sum_{n=0}^{\infty} \frac{(-1)^n x^{n+1}}{n+1}[/tex]
 
Physics news on Phys.org
[tex]\frac{(-1)^n n! x^{n+1}}{(n+1)!}=\frac{(-1)^n x^{n+1}}{(n+1)!/n!}=\frac{(-1)^n x^{n+1}}{(n+1)}[/tex]
 
CRGreathouse said:
[tex]\frac{(-1)^n n! x^{n+1}}{(n+1)!}=\frac{(-1)^n x^{n+1}}{(n+1)!/n!}=\frac{(-1)^n x^{n+1}}{(n+1)}[/tex]

He's everywhere I want to be!