Can Matrix Analysis Simplify Linear and Non-Linear Systems?

r637h
I don't have a problem with drawing up matrices for system solutions, but I'm often puzzled by the answers.

I therefore have avoided matrix analysis, even though it obviously, in a given case, would make a very nice short-cut.
(Especially with computers: Other modalities can be technically more difficult to set up, even with, say, Mathematica).

I'm primarily in "Physics," but math is ,of course, integral. My math has always been crippled via the above.

Any "solutions" suggested?

Thanks, Rudy
 
Mathematics news on Phys.org
Originally posted by r637h
I'm often puzzled by the answers.

r637h,
can you please give an example? Maybe I can then tell what puzzles you.
 
Arcnets:

Many, many thanks.

I'll try to set one up, but I'm not sure I can transmit the equations to this particular modality (miserable failure of copy prior occasions)

Please give me a little time.

I very much appreciate your answer. Rudy
 
OK. Take your time...
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top