Can one diagonalize the Kerr metric?

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Discussion Overview

The discussion centers on the possibility of diagonalizing the Kerr metric in Boyer-Lindquist coordinates. Participants explore theoretical implications, coordinate transformations, and the conditions under which diagonalization may or may not be achievable.

Discussion Character

  • Debate/contested, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant questions whether the Kerr metric can be diagonalized in Boyer-Lindquist coordinates, suggesting that it would simplify calculations.
  • Another participant proposes that transforming to a co-rotating frame could eliminate the off-diagonal term, although they later note that this transformation does not achieve diagonalization.
  • A different participant asserts that diagonalization is not possible due to a theorem by Achille Papapetrou, which requires the metric to be well-behaved on the axis of rotation.
  • One participant queries if diagonalization could be possible everywhere except on the axis of rotation, pondering whether the issue lies in the absence of a general diagonalization or in the matrix being non-diagonalizable.
  • Another participant states that while every spacetime metric is diagonalizable, it may not be possible to find a coordinate basis that achieves this.
  • One participant raises the idea that diagonalizability in a certain coordinate choice might relate to the staticity of the metric, questioning if the non-static nature of the Kerr metric negates the need for theorems regarding diagonalization.

Areas of Agreement / Disagreement

Participants express differing views on the diagonalizability of the Kerr metric, with no consensus reached on whether it can be diagonalized in any coordinate system or under what conditions this might be possible.

Contextual Notes

Participants note the importance of coordinate choices and the implications of the metric's behavior on the axis of rotation, but do not resolve the underlying mathematical complexities or assumptions involved.

arroy_0205
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Is it possible to diagonalize the Kerr metric in the Boyer-Lindquist coordinates? If so then I think calculations with the metric will become easier. I forget under what condition a matrix can be diagonalized. Can anybody remind me?
 
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I think if you transform to a co-rotating frame, the off-diagonal term will be zero. I might try it when I have more time.

[edit] I have since discovered that this transformation does not diagonalise the metric.

M
 
Last edited:
Unfortunately, it is not possible. The reason that one can get as close as one off-diagonal term is a theorem by Achille Papapetrou. This requires that the metric be well-behaved on the axis of rotation. (Roy Kerr)
 
Sorry to bump an old thread, but is it possible to diagonalize the metric every where except on the axis of rotation? In other words, is the problem that no general diagonalization exists, or that it is simply a non-diagonalizable matrix? The second seems improbable to me, since the metric is symmetric and thus always diagonalizable, even unitarily, but I don't know much about the Kerr solution so maybe something weird is going on.
 
Notice who made post #3.

Every spacetime metric is diagonalizable, but not necessarily by a coordinate basis, i.e., there does not necessarily exist a coordinate system that diagonalizes the metric.
 
Isn't diagonalizability in a certain choice of coordinates equivalent to staticity? Since the Kerr metric isn't static, it seems to me that we don't need no fancy theorems as claimed in #3. Am I oversimplifying or getting something wrong?
 

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