Can someone explain elastic band physics

AI Thread Summary
The discussion focuses on using a strength training resistance band to create a device that protects an egg from breaking when dropped from a second-story window. Key physics concepts include modeling the band as a spring using the formula m(d²x/dt²) + β(dx/dt) + kx = f(t), where m is mass, β is the damping coefficient, k is the spring constant, and f(t) is the forcing function. The goal is to achieve an over-damped system with the equilibrium position above ground level. Experimentation is emphasized over precise calculations due to the complexity of real-world variables. Safety precautions, such as wearing goggles during testing, are also advised.
Pianodude132
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in my physics class we have to create a device that will make an egg not break after being dropped from a second story window. my idea was to take a strength training resistance band and use it like a bungee jumping cord and have the egg drop to the bottom without breaking.
what are the formulas for this?
can i have the band weighed down so it doesn't spring back up until after i unhook the egg at the bottom?
thanks
 
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Pianodude132 said:
in my physics class we have to create a device that will make an egg not break after being dropped from a second story window. my idea was to take a strength training resistance band and use it like a bungee jumping cord and have the egg drop to the bottom without breaking.
what are the formulas for this?
can i have the band weighed down so it doesn't spring back up until after i unhook the egg at the bottom?
thanks

You can approximate the bungee cord as a spring and somewhat model it's behavior with ##m\frac{d^2x}{dt^2} + \beta \frac{dx}{dt} +kx = f(t)##. Where m is the mass, ##\beta## is the damping coefficient, k is the spring constant, and f(t) would be the forcing function. k is ## \frac {F}{s} = k## which you can determine experimentally. ##\beta## will depend both on the material you use and the damping effect as the system moves through air. x will be the displacement. f(t) will be zero in this case.

So you basically want to create it so that the system is over-damped, and the equilibrium position is somewhere off the ground of the drop sight. I wouldn't try to calculate this, as the simple model above isn't going to be accurate enough, basically you're going to want to do a lot of trial and error experimentation.

Make sure you wear goggles when playing around, don't want to lose an eye!
 
thanks very much!
 
You could also use a length of string with a short length of elastic to absorb the shock when the string becomes tight.
 
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