(adsbygoogle = window.adsbygoogle || []).push({}); Can someone help me please? This is urgent

I can seem to figure this question out. I'm always left with 4 coins and 1 try.

Using a simple balance, could you (by weighing) find the one fake (lighter) coin in a group of 27 coins. Here's the catch...you may only weigh the coins 3 times. You may not use anything else. How could this be accomplished?

If you can get the answer as fast as possible that would help. Thanks.

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# Can someone help me please? This is

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