Solving a Complex Problem: Analysis and Comparison of Different Approaches

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The discussion focuses on a problem involving tension forces T1 and T2, where the original poster believes their calculations of 3200 N for T1 and 563 N for T2 are correct. However, they are challenged on their assumption that T1y equals 3150 N, which is not supported by the problem's parameters. The correct approach involves recognizing that the only known force is the engine's force of 3150 N, and that T1y cannot equal this value without causing movement in the Y-axis. A geometric solution using a single triangle and the Law of Sines is suggested to find the correct angles and tensions. The discussion emphasizes the importance of accurately interpreting the problem's forces and angles for a valid solution.
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Can anyone help me with this problem? I've uploaded the original problem and the way I solved it. The way they do it, as you can see, is a bit more involved. I did it a bit differently. I also came up with a bit of a different answer. I came up with 3200 N for T1 and for T2, I came up with 563 N. I believe I'm doing it correctly and scanned/uploaded my work so you can see it and was wondering what it is I'm doing incorrectly? Thanks!
 

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T_{1y} isn't equal to 3150 N because there's also the vertical component of the tension of the rope that the worker holds to account for
 
They solved it analytically (with sum of all forces equations)-- you tried to solve it geometrically. Both are valid methods.

williem2 is right. You determined from the get go that T1y = 3150 [N]. Why, exactly? How do you know that? It's not given to you. Not T1 nor T2. The only force you know is the force of the engine, THAT being 3150 [N]. It also doesn't make any sense for T1y to be 3150 [N], because if the engine is 3150 [N] and the force of T1y is 3150 [N], that means that the vector T2y (where the man is pulling) will cause movement in the Y axis since it has a Y component vector and nothing to resist it, as mg and T1y will cancel themselves.

To solve it geometrically-- you only need 1 triangle (since you have 3 vectors emerging from one spot). One vector is vertical (mg), the other vector, T1, is added to that vector in a 10 degree angle (that's given to you straightforwardly)-- now just figure out what's the angle that T2 is added to the mg vector? (hint: it's not 80. Draw it and you will see the answer for yourself). Now just use Law of Sines to get the correct solutions.
 
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