Can the Laplace-ian Problem be Simplified?

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The discussion revolves around the simplification of a complex equation involving the Laplace operator and the wave function Ψ. Participants debate the correct application of the nabla operator, with one suggesting that it can be expressed in terms of the Laplacian. There is clarification on the use of the operator, emphasizing that nabla is a differential linear operator that applies to the right. The conversation highlights the importance of correctly ordering terms when manipulating such equations. Ultimately, the focus remains on finding a clearer representation of the original problem.
Raparicio
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Dear Friends,

I have this problem:

\frac{i\hbar\Psi}{2m}\frac{\partial\nabla\Psi}{\partial t}+(\frac{i\hbar(\nabla\Psi)}{2m}\nabla)\frac{i\hbar(\nabla\Psi)}{2m}

... and i'd like to simplify it... is is possible?

best reggards
 
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The only way i can see it,u may write the laplace-ian in the second term.I assume \Psi to be scalar,hence nabla apllied on it would be the gradient and another nabla would mean laplace-ian...It could mean hessian,but i doubt it is the case here...

Daniel.
 
Like this?

want you mean this?

\frac{i\hbar\Psi}{2m}\frac{\partial\nabla\Psi}{\partial t}+(\frac{i\hbar(\nabla^2\Psi)}{2m})\frac{i\hbar(\nabla\Psi)}{2m}
 
No,i mean this:
\frac{i\hbar}{2m}\Psi \frac{\partial}{\partial t}\nabla \Psi+\frac{i\hbar}{2m}(\nabla\Psi)\frac{i\hbar}{2m}\Delta \Psi

Daniel.

P.S.Nabla is an (differential) linear operator which applies to the right ALWAYS...
 
Sorry,it's the same thing as you have written,it's just that i thought u applied that nabla to the left (else you would have written like i did,without changing the order of terms),instead of to the right...

My applogies,if i assumed a wrong thing...

Daniel.
 
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