Can x=r solve the equations 1/squareroot(x+1)=x and x^3+x^2=1?

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y=1/squareroot(x+1)
y=x

Sketch the two graphs, and indicate on your graph the location of the root r of the equation 1/squareroot(x+1)=x. Use algebra and show that x=r can also solve the equation x^3+x^2=1. Calculate r to 5 significant figurees using simple iteration.


Im stuck in the part in bold. I can rearrange 1/squareroot(x+1)=x into x^3+x^2=1, but how do i show that x=r can solve the equation? Thanks.
 
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hi gomes! :smile:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)
gomes. said:
Im stuck in the part in bold. I can rearrange 1/squareroot(x+1)=x into x^3+x^2=1, but how do i show that x=r can solve the equation? Thanks.

there isn't really anything to prove …

"r is the root of 1/√(x+1) = x" is just another way of saying that 1/√(r+1) = r :wink:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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