Can you help me find what a = on this problem?

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The discussion revolves around solving a physics problem involving acceleration 'a' of blocks in a system. Participants clarify the equations needed, with one asserting that the acceleration should be 15/4 based on their calculations. The use of Newton's second law and free body diagrams is emphasized as crucial for deriving the correct equations. There is some confusion regarding the values used, particularly with the coefficients of friction and the final result. Ultimately, the consensus confirms that the correct acceleration is indeed 15/4.
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550615.jpg


Sorry about bad picture. I did best I could but I am not sure that's how I do this problem.
If I am wrong can you give me right equations for this? Thank you. :)
 
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about a

can you specify which block has acceleration 'a'.
 
i have no clue. That's how my teacher wrote the problem as take home problem. He just had pictures and what is a = ? I think he meant total acceleration. He gave us similar problems few weeks ago but it was on two boxes without mk instead of box and triangle with mk. So I used formula to find acceleration of each blocks and found T1 and T2 and then applied to same formula he used on the problem he did few weeks ago. :(
 
a

a should be 15/4.
(i used g=10 not 9.8)
the acceleration of each block is the same.
 
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hmm.. 15/4? how did you end up with that?
 
explanation

T1=10a
T2-10gsin30=10a
20g-(T1+T2)=20a

solve these to find "a".
 
err.. I can't really tell how your equation works with that 3 short equations. Did you use mk = .1 and mk = .2 on each side to get the answer?
 
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do you know the Newtons second law.
ƩFx=max
ƩFy=may

first draw the free body diagram of each block and then apply these eqns to get my above eqns
 
but you sure it's 15/4 not 15/40? when I plug in my t1 and t2 and solve for a using your 3 line equation, I get 15/40
 
  • #10
yes

yes it is 15/4 only
 
  • #11
yes

thats correct
 
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