Can You Help Verify This Calculus Derivative Solution?

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A fourteen-year-old is self-studying calculus and seeks verification of their derivative solution for the expression (x^3 - x^2) + (3x). The initial calculation has some typos, but the final answer of 3x^2 - 2x + 3 is confirmed as correct. Users suggest utilizing Wolfram Alpha for derivative checks and recommend learning LaTeX for better formatting of mathematical expressions. The discussion emphasizes the importance of learning from mistakes and encourages the young learner in their studies. Overall, the community provides constructive feedback and resources to aid in understanding calculus.
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Hello, I am fourteen and "attempting" to teach myself calculus I was wondering if anyone with prior calculus knowledge would be willing to solve this derivative in order to check my answer.d
---- (x^3-x^2)+(3x)
dx
(My thought process)

d-----------------d
=--- (x^3-x^2)+---(3x)
dx---------------dx

=3x^(3-1)-2x^(3-1)+3x

=3x^2-2x+3

=3x^2-2x+3Sorry if I screwed that up.
 
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I wouldn't worry too much about embarrassing yourself. Everyone here had to learn this stuff at some time and probably made the same kinds of mistakes as everybody else.

You can use www.wolframalpha.com to find derivatives. Just enter "derivative of (x^3-x^2)+(3x)".
 
Thanks for the help
 
You have a couple of typos in your work, but your method and final answer are correct.
 
Jake Minneman said:
Thanks for the help
Yes I got it
 
Jake Minneman said:
Hello, I am fourteen and "attempting" to teach myself calculus I was wondering if anyone with prior calculus knowledge would be willing to solve this derivative in order to check my answer.


d
---- (x^3-x^2)+(3x)
dx
(My thought process)

d-----------------d
=--- (x^3-x^2)+---(3x)
dx---------------dx

=3x^(3-1)-2x^(3-1)+3x
In the line above, it should be
=3x^(3-1)-2x^(2[/color]-1)+3[STRIKE]x[/STRIKE]
Jake Minneman said:
=3x^2-2x+3

=3x^2-2x+3


Sorry if I screwed that up.
 
Mark44 said:
In the line above, it should be
=3x^(3-1)-2x^(2[/color]-1)+3[STRIKE]x[/STRIKE]

Thank you the typing of the question has been giving me trouble.
 
You might want to look into how to format things using LaTeX. You can click any of the lines below to see what I did.
\frac{d}{dx}(x^3 - x^2 + 3x)
=\frac{d}{dx}x^3 - \frac{d}{dx}x^2 + \frac{d}{dx}3x
=3x^{3 -1} - 2x^{2 -1} + 3x^{1 - 1}
=3x^2 - 2x + 3
 
Mark44 said:
You might want to look into how to format things using LaTeX. You can click any of the lines below to see what I did.
\frac{d}{dx}(x^3 - x^2 + 3x)
=\frac{d}{dx}x^3 - \frac{d}{dx}x^2 + \frac{d}{dx}3x
=3x^{3 -1} - 2x^{2 -1} + 3x^{1 - 1}
=3x^2 - 2x + 3

This helped tremendously
 
  • #10
Glad to hear it!

There are a few LaTeX tags that I use a lot.
Integral - [ tex] \int f(x) dx [ /tex]
Definite integral - [ tex] \int_{a}^{b} f(x) dx [ /tex]
Fraction or rational expression - [ tex] \frac{x + 2}{x^2 - 4}[ /tex]
Limit - [ tex] \lim_{x \to 0} f(x) [ /tex]

If you remove the extra spaces I added in the tex tags, the expressions above render like this:

\int f(x) dx
\int_{a}^{b} f(x) dx
\frac{x + 2}{x^2 - 4}
\lim_{x \to 0} f(x)
 
  • #11
thats sweet
 
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