Can You Solve These Advanced Calculus Integrals?

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Homework Help Overview

The discussion revolves around advanced calculus integrals, specifically focusing on two integrals: one involving a rational function and the other involving a combination of trigonometric and logarithmic functions. Participants are exploring methods for integration and discussing the nature of the problems presented.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Some participants suggest using partial fractions for the first integral, while others mention integration by parts for the second integral. There is also a discussion about the singularities of the function in the first integral and the implications for integration.

Discussion Status

The discussion has seen various approaches being proposed, with some participants questioning the appropriateness of the problems in the context of homework help. There is no explicit consensus on the methods to be used, and the conversation reflects differing opinions on the nature of the questions posed.

Contextual Notes

There are indications that the original poster's intent may not align with the forum's guidelines regarding homework-like questions, leading to a discussion about the rules and expectations within the forum.

Ratio Test =)
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Hello :)
Here we go! :


1. [tex] \int \frac{dx}{x^3+x^2+x+1}[/tex]

2. [tex] \int_{\frac{\pi}{2}}^{\pi} \left( sin(x) ln(x) - \frac{cos(x)}{x}\right) dx[/tex]

Do your best :)
 
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1 + x + x^2 + x^3 = (1-x^4)/(1-x)

So, we have to integrate -(x-1)/(x^4 - 1)

The singularities of this function are at x = -1, i and -i, so the partial fraction decomposition is:

-1/2 1/(x+1) +1/4 (1+i)/(x-i) + 1/4 (1-i)/(x+i)

The integral is thus given by:

-1/2 Log(x+1) + 1/4 (1+i)Log(x-i) + cc of last term. =

-1/2 Log(x+1) + 1/2 Re[(1+i)Log(x-i)]

Real and imaginary parts of logarithms of complex arguments are easily obtained as follows. We have:

Log[r exp(i theta)] = Log(r) + i theta

This means that:

Log(x + i y) = 1/2 Log(x^2 + y^2) + i arctan(y/x)

The integral is thus given by:

-1/2 Log(x+1) + 1/4 Log(x^2 + 1) + 1/2 arctan(1/x)

-1/2 Log(x+1) + 1/4 Log(x^2 + 1) - 1/2 arctan(x)

(pi absorbed in integration constant which we don't write down)
 
Last edited:
Um, I believe #1 is just partial fractions, while #2 is integration by parts. No need to be fancy :)
 
sin(x)ln(x)-cos(x)/x=(-cos(x))'ln(x)+(-cos(x))(ln(x))'=(-cos(x)ln(x))'
 
Ratio Test =) said:
Hello :)
Here we go! :


1. [tex] \int \frac{dx}{x^3+x^2+x+1}[/tex]

2. [tex] \int_{\frac{\pi}{2}}^{\pi} \left( sin(x) ln(x) - \frac{cos(x)}{x}\right) dx[/tex]

Do your best :)


Welcome to the PF, Ratio. We generally do not allow homework-like brain teasers here on the PF, for obvious reasons. Please do not post this type of question again. I've moved this question to the Homework Help forums, and the normal homework rules apply (we don't do these types of questions for students).
 
berkeman said:
Welcome to the PF, Ratio. We generally do not allow homework-like brain teasers here on the PF, for obvious reasons. Please do not post this type of question again. I've moved this question to the Homework Help forums, and the normal homework rules apply (we don't do these types of questions for students).


One Question : Who told you this is for my homework ?
Did you read the thread's title ?
 
Ratio Test =) said:
One Question : Who told you this is for my homework ?
Did you read the thread's title ?

Don't imply I'm an idiot. If you don't understand why homework questions aren't allowed as brain teasers, please think about it a bit more. And re-read the PF Rules link at the top of the page that you agreed to when you joined here.

Thread locked. Show some brains people.
 

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