Can You Solve This Third Order Homogeneous Differential Equation?

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Is this diff eq solvable? !

Homework Statement


Find the general solution to the third order homogeneous diff eq if one solution is known to be:

x^2e^{5x}


I was thinking of using reduction of order but I don't have the original equation!
 
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Okay. Since it was given that the 3rd order diff eq is homogeneous, it is okay to assume that there is no particular solution to this, right?

And I can also assume that (m-5) is a factor of the characteristic equation. I am also assuming that it is a thrice repeated root, so y=c_1e^{5x}+c_2xe^{5x}+c_3x^2e^{5x}

I am not so confident in this, since it is all based on assumption. Any thoughts on the validity of this?
 
It might help a bit if you told us what the differential equation was.
 
d_leet said:
It might help a bit if you told us what the differential equation was.

Read the OP. It has not been given.
 
Saladsamurai said:
Okay. Since it was given that the 3rd order diff eq is homogeneous, it is okay to assume that there is no particular solution to this, right?

And I can also assume that (m-5) is a factor of the characteristic equation. I am also assuming that it is a thrice repeated root, so y=c_1e^{5x}+c_2xe^{5x}+c_3x^2e^{5x}

I am not so confident in this, since it is all based on assumption. Any thoughts on the validity of this?

Assuming this is a linear homogeneous 3rd order diff eq with constant coefficients, then that is the case and the differential equation must be (D- 5)3y= y"'-15y"+ 75y'- 125y= 0. Of course, we were not told that.
 
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So, as it stands, this problem has been worded incorrectly. That is what I thought. Thank you.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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