- #1
Coco12
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A load has a power rating of 160 w when the current is 6.0 A. What will be the power output if the current increases to 15 A?
I know how to do it : use the formula v=I^2R
In this case 15/6 = 2.5^2 = 6.25
160 * 6.25 = 1000W.
My question is why can't you use p = VI ? Because in this case , it would be 160* 2.5?
I know how to do it : use the formula v=I^2R
In this case 15/6 = 2.5^2 = 6.25
160 * 6.25 = 1000W.
My question is why can't you use p = VI ? Because in this case , it would be 160* 2.5?