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__1. Homework Statement :__A cannonball is catapulted toward a castle. The cannonball's velocity when it leaves the catapult is 34 m/s at an angle of 55° with respect to the horizontal and the cannonball is 8.0 m above the ground at this time.

(a) What is the maximum height above the ground reached by the cannonball?

(c) What are the x- and y-components of the cannonball's velocity just before it lands? The y-axis points up.

## Homework Equations

Maximum height = Yf=Yo+Voy*t+1/2gt^2

Voy=34sin55=27.85 m/s

Vf=Vo+at=0=27.85-9.8t t=2.8s

Maximum height= 47.56 m

How do I find the x and y components? what equations do I need?