Capacitance: 24µF, 30V - Calculate Charge

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To find the charge on a 24-µF capacitor with a 30 V potential difference, the relevant formula is C = q/U, where C is capacitance, q is charge, and U is voltage. By rearranging the formula, charge can be calculated as q = C * U. Substituting the values, q = 24µF * 30V results in a charge of 720µC. Understanding the concept of capacitance is crucial for solving such problems. This approach provides a clear method to calculate the charge on a capacitor.
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Homework Statement



A 24-µF capacitor has an electric potential difference of 30 V across it. What is the charge on the capacitor?

Homework Equations



kq1q2/r2?, q/change in V?

The Attempt at a Solution


ive tried looking through my notes but i was absent don't understand this if you could give me a step by step i would appreciate it.
 
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Hi isuck@physics, welcome to PF.
The relevant equation given by you is wrong. Search for the relation between capacitance , potential difference and the charge in a capacitor.
 
Do you really understand the concept of capacitance?
Just put the figures into the formula of definition
\[<br /> C = \frac{q}{U}<br /> \]<br />
 

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