Capacitance of a System (Spherical Conducting Shells)

GermanMC
Messages
6
Reaction score
0

Homework Statement


A spherical conducting shell of radius 0.1 m has a free charge of -2 μC. It is surrounded by a concentric spherical conducting shell of radius 0.12 m carrying a free charge of -2 μC. Between the shells is a dielectric material of dielectric constant 10 εo. If the dielectric material is linear, what is the capacitance of the system?


Homework Equations


C=(Q/V)=4πεo(ab/a-b)


The Attempt at a Solution



I attempted the solution with only the above equation, I'm just not sure how to to include the dielectric constant in my answer. The instructions say that I should use one of Maxwell's Equations. How do I make the connections I need?
 
Physics news on Phys.org
GermanMC said:

Homework Statement


A spherical conducting shell of radius 0.1 m has a free charge of -2 μC. It is surrounded by a concentric spherical conducting shell of radius 0.12 m carrying a free charge of -2 μC. Between the shells is a dielectric material of dielectric constant 10 εo. If the dielectric material is linear, what is the capacitance of the system?


Homework Equations


C=(Q/V)=4πεo(ab/a-b)


The Attempt at a Solution



I attempted the solution with only the above equation, I'm just not sure how to to include the dielectric constant in my answer. The instructions say that I should use one of Maxwell's Equations. How do I make the connections I need?

Nvm, I feel that I have the kinks worked out.
 
I was going to say, the first thing is to ignore the bit about the -2μC charges!
 
Bingo. Free charge didn't matter.
 
GermanMC said:
Bingo. Free charge didn't matter.

It might have if the dielectric were nonlinear, but colleges don't pull stuff like that on you!
(In that case, C would have to be defined as dq/dV instead of q/V, or "incremental capacitance" instead of just "capacitance". Many types of real-life capacitors do display some nonlinearity, matter of fact.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top