Capacitance per length unit of coaxial cable

AI Thread Summary
The discussion focuses on calculating the capacitance per unit length of a coaxial cable with given dimensions and dielectric constants. The user applied Gauss's law to derive the electric field and voltage, ultimately calculating a capacitance of 288 pF/m, which contradicts the book's solution of 144 pF/m. Concerns were raised about the application of Gauss's law and the inclusion of local dielectric constants in the calculations. The user also noted a discrepancy in units, suggesting a potential error in their approach. Clarification on these calculations is sought to resolve the factor of 2 difference in capacitance values.
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Homework Statement


Coaxial cable has double layered dielectric.
a=2mm, b=4mm, c=8mm, εr1=3, εr2=4.5, Uab=1000V
1. Calculate capacitance per unit length of a cable.
2. Calculate inner and outer charge densities of a cable.
2. Homework Equations

Gauss law
C'=Q'/U
σ = nD
σp = nP

3. The Attempt at a Solution

After applying Gauss law for dielectrics, I get electric field:
E=Q'/(2πε0r1r2r)).
Limits of integration for voltage: (a - b) + (b - c)
U=(Q'(ln(b/a)+ln(c/b)))/(2πε0r1r2))


Then, C'=(2πε0r1r2))/(ln(b/a)+ln(c/b))
This gives me C'=288pF/m but in my books solution it is C'=144pF/m.

Could someone check this.
Thanks for replies.
 

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E shouldn't have the same formula in both parts, it has to include the local ε somehow. Also, in the way you wrote it the units do not match.
I'm surprised that your answer seems to be exactly a factor of 2 off with this, however.
 
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