Capacitor Banks Variation With Voltage and Frecuency

AI Thread Summary
To determine the resulting power of a 480 V, 200 kVAr capacitor bank when moved to a location with 390 V and 50 Hz, one must first calculate the capacitive reactance at 60 Hz using the formula X_{60} = P/V^2. The reactance at 50 Hz can then be derived with the ratio X_{50}/X_{60} = 60/50. By substituting the new voltage of 390 V into the equation, the new power rating of the capacitor bank can be calculated. This process ensures accurate adjustments for changes in voltage and frequency. Understanding these calculations is crucial for effective capacitor bank management.
biguelo
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Hi,

I have a 480 V, 200 kVAr and 60 Hz capacitor bank. I need to move this bank to a location with 390 V and 50 Hz, I wonder what would be the resulting power of the bank.

Regards.
 
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Find value of capacitive reactance at 60 Hz
X_{60}=\frac{P}{V^2}. Now its value at 50 Hz is found from
\frac{X_{50}}{X_{60}}=\frac{60}{50}.
From the value of X_{50} and using new voltage 390 V you can find resulting power rating of your capacitor bank.
 
Thanks for the reply.
 
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