Capacitor Connections and Charge Conservation

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AI Thread Summary
In the discussion on capacitor connections, two capacitors, C1 (2.4uF at 880V) and C2 (4.0uF at 560V), are analyzed for their final voltage and charge after being connected in different configurations. When the positive plates are connected together, charge conservation allows for the calculation of the final voltage and charge on each capacitor using the formula Q=CV. However, when the capacitors are connected negative to positive, the approach changes, as the effective capacitance and voltage differ significantly. The total charge remains conserved in both scenarios, but the resulting voltages and charges are lower in the second case. Understanding these principles is crucial for solving capacitor connection problems effectively.
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Homework Statement


a capacitor C1 2.4uF charged to a voltage of 880V and a second capacitor C2 4.0uF charged to 560V. They are disconnected from their batteries and their positive plated and connected together, and their negative plated are connected together. What will the final voltage and charge on each be after a long time? They are then connected negative to positive..and same question as before.


Homework Equations


Q=CV


The Attempt at a Solution


I don't really have a clue. However, I found the charge on each capacitor initially then added them together, and found the percent for each capacitor (C1/(C1+C2)) and times it by the total charge. Does that even make sense? because the answer was right. Are you able to add the capacitors in any way? are they in series or parallel? the voltages of them were the same as if they were in parallel. AH!
 
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Find the charge Q1 on C1 and Q2 on C2.

The total charge has to be conserved.

Then find the combined capacitance in parallel, and find the voltage based on the total charge and effective capacitance.
 
Astronuc said:
Find the charge Q1 on C1 and Q2 on C2.

The total charge has to be conserved.

Then find the combined capacitance in parallel, and find the voltage based on the total charge and effective capacitance.

This works for the first case where the 2 positive ends are connected. In the second case where the positive is connected to the negative of the other it doesn't..whether you add the capacitances in parallel or series?! The voltage and charge on each is much smaller.
 
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