A capacitor C1 carries a charge Q0. Is is then connected directly to a second, uncharged, capacitor C2.(adsbygoogle = window.adsbygoogle || []).push({});

What charge will each carry now?Q1 = Q0C1/(C1 + C2); Q2 = Q0C2/(C1 + C2)

What will be the potential difference across each?

V = Q0 / (C1 + C2)

-------||-------||--------

|*****C1*****C2******|

|********************|

|********************|

|********************|

|_______________________|

I know that the formula Q = CV is used, but how do you manipulate it (other than V = Q/C) to get the answers in bold?

Thanks.

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# Homework Help: Capacitor homework problem

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