Capacitor in parallel with resistor

AI Thread Summary
In the discussed circuit, an effective resistor is in parallel with an effective capacitor, each consisting of two components in series. Initially, when the capacitors are uncharged, all current flows through them, resulting in a zero voltage drop across the capacitors and no current through the resistors. This leads to confusion as the total voltage drop should equal the battery's voltage, yet calculations suggest a zero voltage drop. The circuit's setup involves a battery providing a voltage (e.g., 24V) to both the resistor and capacitor, implying they should share the same potential. The discussion highlights a contradiction between Kirchhoff's law and the observed voltage analysis, prompting a request for clarification on the circuit configuration.
galoisien
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(another problem but less differential equations-sy)


Consider a circuit where there is an effective resistor in parallel with an effective capacitor.

Each effective capacitor consists of two capacitors in series, same for the resistor.

Now, when the capacitors are uncharged, all the current is flowing through the capacitors and not through the resistors.

However, since the capacitors are uncharged, the voltage drop across them is zero. Since there is no current through the resistors, the current through them is also zero.



But the total voltage drop must be the voltage drop of the battery! Yet I seem to be getting zero!
 
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galoisien said:
(another problem but less differential equations-sy)


Consider a circuit where there is an effective resistor in parallel with an effective capacitor.

Each effective capacitor consists of two capacitors in series, same for the resistor.

Now, when the capacitors are uncharged, all the current is flowing through the capacitors and not through the resistors.

However, since the capacitors are uncharged, the voltage drop across them is zero. Since there is no current through the resistors, the current through them is also zero.



But the total voltage drop must be the voltage drop of the battery! Yet I seem to be getting zero!

Could you please describe the circuit in better detail? At first there are two caps in parallel with two resistors, but at the very end you introduce a battery? Where is the battery?
 
Sorry the battery provides a voltage E (i.e. 24V) to both the effective resistor and capacitor -- i.e. theoretically both the resistor and capacitor should have the same potential.

Kirchoff's law says it should be 24V, but other analysis says 0V. I am confused.

(also the two-resistor, two-capacitor thing was to allow an analysis of comparing the potentials of0 point between the two resistors and the point between the two capacitors).
 
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