Capacitor with a conducting core

AI Thread Summary
A cylindrical capacitor with a solid conducting core and a hollow conducting tube is described, with specific dimensions and a potential difference of 6.40 V. The calculations for charge per length, total charge, capacitance, and energy stored are discussed, but initial attempts at using formulas yielded incorrect results. The correct formula for capacitance is clarified, emphasizing that the natural log should be in the denominator. The corrected capacitance formula is confirmed as C = 2 pi εo L / ln(r2/r1). Accurate calculations are essential for determining the capacitor's properties effectively.
sonrie
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A 0.380 m long cylindrical capacitor consists of a solid conducting core with a radius of 1.15 mm and an outer hollow conducting tube with an inner radius of 2.05 mm . The two conductors are separated by air and charged to a potential difference of 6.40 V .

Calculate the charge per length for the capacitor.

lambda =_______ C/m.

Calculate the total charge on the capacitor.

Q=_____ C.

Calculate the capacitance.

C=______ F.

Calculate the energy stored in the capacitor when fully charged.

U=_______ J.

Well i figure out a couple of equations to use but i seem to get them wrong! all are wrong! Any Help!
so the equation i used were :



To Find C = 2 pi €o L ln(r2/r1) = 12.22 *10^-12 F = 12.22 pF.
To Find U = (1/2) C V^2 = 250*10^-12 J = 250 pJ.
To Find Q = C V = 78.2*10^-12 C = 78.2 pC
To Find lambda = Q/L = 2.06*10^-10 C/m = 206 pC/m.
 
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sonrie said:
To Find C = 2 pi €o L ln(r2/r1) = 12.22 *10^-12 F = 12.22 pF.

Hi sonrie,

This is the wrong formula for the cylindrical capacitor. The natural log is in the denominator.
 
so the formula should read C= 2 pi Eo L/Ln (r2/r1) Is that correct?
 
That looks right to me.
 
Your the Best! Thank You!
 
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