Carboxylation of sodium phenolate

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The discussion focuses on the carboxylation of sodium phenolate when it reacts with carbon dioxide and then acid. The proposed mechanism involves electrophilic aromatic substitution, where the positive partial charge on the carbon in CO2 facilitates the reaction. The -ONa group is considered electron-withdrawing, making the ortho and para positions more reactive, leading to the formation of ortho- and para-hydroxybenzoic acids. There is clarification regarding the correct nomenclature, with sodium phenolate being the accurate term instead of sodium benzoate. The expected product distribution is approximately 66% ortho and 33% para.
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Homework Statement



Predict the products and reaction mechanism when sodium phenolate reacts with carbon doixide, then acid.

Homework Equations



Sodium phenolate: Ph-ONa
Carbon Dioxide: O=C=O

The Attempt at a Solution



The carbon atom in CO2 has a positive partial charge, so I expect an electrophilic aromatic substitution mechanism. The hydrogen which is released will protonate one of the oxygen atoms and make a carboxy group. The result is a carboxylation of the original compound. The -ONa group is electron withdrawing, so only the orto and para positions are susceptible. Then, the acid will remove the sodium and protonate the oxygen to form an alcohol group.

The products will then be orto-hydroxybenzoic acid, or 2-hydroxybenzoic acid, and para-hydroxybenzoic acid, or 4-hydroxybenzoic acid. I expect roughly 66% orto and 33% para among the products.
 
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espen180 said:

Homework Statement



Predict the products and reaction mechanism when sodium benzoate reacts with carbon doixide, then acid.

Homework Equations



Sodium benzoate: Ph-ONa
Carbon Dioxide: O=C=O

The Attempt at a Solution



The carbon atom in CO2 has a positive partial charge, so I expect an electrophilic aromatic substitution mechanism. The hydrogen which is released will protonate one of the oxygen atoms and make a carboxy group. The result is a carboxylation of the original compound. The -ONa group is electron withdrawing, so only the orto and para positions are susceptible. Then, the acid will remove the sodium and protonate the oxygen to form an alcohol group.

The products will then be orto-hydroxybenzoic acid, or 2-hydroxybenzoic acid, and para-hydroxybenzoic acid, or 4-hydroxybenzoic acid. I expect roughly 66% orto and 33% para among the products.


2 things spring to mind, 1) PhONa is not sodium benzoate. 2) are you sure about your directive effects?
 
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1) A mistake on my part. The problem gave the structure, not the name. It should be sodium phenolate. I'll correct the opening post.

2) About the regiochemistry, my thinking is that since the hydroxy group is orto/para-directive, then a -ONa group should be so too, even more so, since the electronegativity of Na is less than that of H, meaning more electron density near the oxygen.
 
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espen180 said:
1) A mistake on my part. The problem gave the structure, not the name. It should be sodium phenolate. I'll correct the opening post.

2) About the regiochemistry, my thinking is that since the hydroxy group is orto/para-directive, then a -ONa group should be so too, even more so, since the electronegativity of Na is less than that of H, meaning more electron density near the oxygen.

Fair enough. My point two was based on the structure being benzoate, rather than phenolate. You may also want to, if you still can, amend the title of the thread as well :)
 
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sjb-2812 said:
You may also want to, if you still can, amend the title of the thread as well :)

Espen can't :wink:
 
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