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Cariolis Effect

  1. Nov 15, 2012 #1
    1. The problem statement, all variables and given/known data

    The question is self developed. After the lecture from our professor over Coriolis Effect, we decidable to be over ambitious and derive the equation and somehow calculate the force exerted on a given location on the earth or "For example we throw a ball in a train travelling opposite the direction of the Coriolis effect - But someone said that would be possible if it is going inside down the Earth (Somebody can correct me If I am wrong)


    2. Relevant equations



    3. The attempt at a solution

    We have not attempted but just drived to get the general equation and read several pages about it. I would like someone to attach some notes for Coriolis effect and put us in the right direction ! I would also like if someone gives us a question to solve, a exciting question, through which we can learn in detail the application of Coriolis effect.
     
  2. jcsd
  3. Nov 15, 2012 #2

    Simon Bridge

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    The coriolis effect comes out of the transform to a rotating reference frame - just like the centrifugal effect. You do not have to be descending into the Earth to see the effect.

    Like the centrifugal effect, you can model it with a pseudoforce while treating the rotating frame as stationary. You can look up all these terms online.
     
  4. Nov 15, 2012 #3

    haruspex

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    It isn't really a force. Do you understand that there is really no such thing as centrifugal force? Both "forces" arise from using a frame of reference that's accelerating. This gives the illusion of forces because of the way things seem to behave.
    If you take an inertial frame of reference then you can see that the objects are doing what Newton said they should do - continue at a steady speed in a straight line if there's no net force on them.
    What would be the "opposite direction"?
    The Coriolis effect should be observable with a projectile in any horizontal direction. It is an apparent deflection to the right in the northern hemisphere and to the left in the southern. Its magnitude depends on distance from the equator (zero at the equator) and time and distance of trajectory, but not on orientation of trajectory.
    Yes, an apparent deflection should also be observable for vertical trajectories, but I'm not sure it would be right to call that a Coriolis effect, though it's really the same thing going on. In this case it would be to the East downwards and to the West upwards.
    Before conducting an experiment, figure out the trajectory you would need in order to observe an effect. Feel free to post your equations and calculations here.
     
  5. Nov 16, 2012 #4
    I am very pleased to hear from you all !

    I really appreciate it.

    I would like to post all my calculations here but first - Kindly tell me some points on how to start. Our professor (He filled the whole board with differentiation of trignometic funtions as vectors which I didn't really understand) -- I want someone to explain me discursively and give me points over it.

    I want to calculate the Coriolis effect for example at a given place on Earth (Let's assume a country) - Can someone jought down the points for me what I'll have to do to calculate the force acting on i.e (any object, make it easy for me and give me a suitable object which I should assume)

    We friends really want to do this and we'll keep it updated here - Our aim is to calculate a force and go through all the mathematics in it so that we can experience and have a further understanding of it -- (Our Professor mentioned, its hard to explain but with Mathematics, one actually see's this perceived movement of object) - We want to experience that.
     
  6. Nov 16, 2012 #5
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