Cathode Ray Tube: Deflection on Screen with 480V & 36V, 960V & 18V

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In a Cathode Ray Tube, the screen deflection is 2.4cm at an accelerating voltage of 480V and a deflecting voltage of 36V. The deflection is directly proportional to the deflecting voltage and inversely proportional to the electron's velocity, which is influenced by the accelerating voltage. When the accelerating voltage increases to 960V and the deflecting voltage decreases to 18V, the kinetic energy of the electrons also increases. This change in parameters will affect the overall deflection observed on the screen. The problem requires calculation based on these principles to determine the new deflection value.
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In a Cathode Ray Tube, the deflection on the screen is 2.4cm when the accelerating voltage is 480V, and the deflecting voltage is 36V. What deflection will you see on the screen if the accelerating voltage is 960V and the deflecting voltage is 18V?
 
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Some hints...The deflection is proportional to the deflection voltage. But it's inversely proportional to the velocity of the electron, since a faster electron spends less time between the deflection plates than a slower one. Finally, the kinetic energy of an electron is proportional to the acceleration voltage.
 
um...so...
 
gillgill said:
um...so...
I've given you everything you need to know to solve the problem. I'm certainly not going to solve it for you!
 

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