Cathode Rays & Velocity: Uniform or Accelerated?

AI Thread Summary
Cathode rays, or streams of electrons, are emitted from the cathode in a discharge tube and gain significant velocity due to the applied electric field between the electrodes. The electrons are accelerated by this external electric field, which is why their speed can be calculated using the formula v = sqrt(2*p.d.*e/m), where p.d. is the potential difference. The confusion arises from whether the velocity is uniform or continuously increasing; however, the primary acceleration occurs due to the electric field. The discussion clarifies that while electrons start with negligible speed, they are indeed accelerated by the field, leading to their high velocity. Understanding this interaction is crucial for accurately calculating their speed in such experiments.
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During discharge tube experiment, the cathode rays are emitted from cathode at very low pressure...it is said that these rays move at very high velocity(if we apply high Potential Difference between 2 electrodes)...do these rays( stream of electrons) travel in uniform velocity or aren't they accelerated due to presence of external electric field?why do we directly find out the velocity of electron by the formula v=sq.rt(2*p.d.*e/m) ? i am confused whether the velocity of electrons is uniform or it is being accelerated by the external electric field??
 
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mysteriously said:
During discharge tube experiment, the cathode rays are emitted from cathode at very low pressure...it is said that these rays move at very high velocity(if we apply high Potential Difference between 2 electrodes)...do these rays( stream of electrons) travel in uniform velocity or aren't they accelerated due to presence of external electric field?why do we directly find out the velocity of electron by the formula v=sq.rt(2*p.d.*e/m) ? i am confused whether the velocity of electrons is uniform or it is being accelerated by the external electric field??

While the electrons are emitted with some velocity, the overwhelming majority of the energy/speed picked up by the electrons are from the applied field. Remember, these are electrons! They are charged particles. Charged particles can interact with an external electric field. So you apply such a field to cause them to speed up.

If you apply a potential difference of V, then the energy gained by the electrons is eV = 1/2 mv^2 (assuming non-relativistic). So calculate your speed from there (assuming it started with 0 or negligible speed, which is a valid assumption in most cases).

P.S. This is not a "Quantum Physics" topic and has been moved out of that forum.

Zz.
 
dont they accelerate in the electric field?every charged particle in electric field is accelerated...then what and at what time is the velocity we calculate from above formula??
 
mysteriously said:
dont they accelerate in the electric field?every charged particle in electric field is accelerated...then what and at what time is the velocity we calculate from above formula??
You have a tube with a cathode at one end. Where is the anode?
 
mysteriously said:
dont they accelerate in the electric field?every charged particle in electric field is accelerated...then what and at what time is the velocity we calculate from above formula??

This is utterly puzzling. What did you think I meant when I said that these charge particles interact with electric field?

And why can't you just calculate the velocity? I've given you everything you need already!

Zz.
 
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