- #1

sally21

- 3

- 0

## Homework Statement

The thickness of the object is 2 cm. The density of the material (pronounced row) is 7800. The angle (theta) is pi/6. The radius is .75 meters. What is the moment of inertia and

the center of mass?

Here is what the object looks like:

http://www13.zippyshare.com/v/36721619/file.html

The object is rotating around the origin.

## Homework Equations

None given

## The Attempt at a Solution

Okay, so I have no idea how to find the center of mass for this object. I know you have to use integration, but the other kid in my class was using triple integration (which is something I don't know and I don't know if he was right any way). So I have no idea how to find the center of mass for this object.

As for the moment of inertia, I think that the moment of inertia will be 1/12 of the moment of inertia of a cylinder. I figure this because pi/6 = 30 degrees. 360/30=12. So I think that the moment of inertia will be:

I= 1/2m[(r1^2)+(r2^2)] * 1/12

this is just the moment of inertia formula for a hollow cylinder and I multiplied it by 1/12.

Thank you very much for helping me in any way!!!