Center of mass particle problem

AI Thread Summary
To find the speed of the heavier particle approaching the center of mass, the formula V_cm = (m1v1 + m2v2) / (m1 + m2) is used, where m1 and m2 are the masses of the particles and v1 and v2 are their velocities. The center of mass for a two-particle system can be calculated using this equation. For the momentum of the lighter particle relative to the center of mass, the linear momentum is determined by multiplying its mass by its relative velocity. Understanding how to apply these formulas is essential for solving problems related to the center of mass in particle systems. Accurate calculations require careful attention to detail in the equations used.
pringless
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A 4.01g particle is moving at 1.36 m/s toward a stationary 9.43g particle. With what speed does the heavier particle approach the center of mass of the two partciles?

i don't get how cm relates to finding speed

The mass of a star like our sun is 347000 Earth masses, and the mean distance from the center of this star to the center of a planet like our Earth is 6.63*10^8 km. Treating this planet and start as particles, with each mass concentrated at its respective geometric center, how far from the center of the star is the center of mass of the planet-star system? Answer in units of km.
 
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Well, how do you find the center of mass of a two particle system?
 
is it like V_cm = m1v1+m2v2 / m1 + m2?
 
Originally posted by pringless
is it like V_cm = m1v1+m2v2 / m1 + m2?

You probably meant
V_{cm}=\frac{m_1v_1+m_2v_2}{m_1+m_2} which is correct. You should be carefull to put your parens in where necessary.
 
thx nate..
i have one more question for that first problem.

how would you calculate the magnitude of momentum of the lighter particle relative to the center of mass?
 
Linear momentum is mv.
Since you know the mass already, so all you have to do is figure out the relative velocity.
 
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