Centripetal Acceleration metres per second squared

AI Thread Summary
To find the centripetal acceleration of a point on a bicycle wheel with a radius of 0.32m rotating at 22 rad/s, the formula a_c = v^2 / r is used. The tangential velocity (v) can be calculated using the relationship v = rω, where ω is the angular velocity. By substituting the values, the tangential velocity is determined, which is then used to calculate the centripetal acceleration. The discussion emphasizes the importance of understanding the relationship between linear and angular motion. Clear explanations and step-by-step guidance are appreciated in solving such problems.
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Homework Statement


What is the magnitude of the centripetal acceleration of a point on the circumference of a 0.32m radius bicycle wheel rotating at 22 rad/s ?

Give your answer in metres per second squared


Homework Equations


To be honest I am stumped I have no idea


The Attempt at a Solution


I am lost.

Please help!
 
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centripetal acceleration is given by

a_c=\frac{v^2}{r}

where r is the radius which you can find since circumference is given. v is tangential velocity
you have been given angular velocity \omega. the relation between
tangential velocity and angular velocity is

v=r\omega
 
Thank you!
 
thanks so much for explaining why this is so clearly!
 
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