Centripetal Acceleration of washer spin cycle

[CursedAntagonis]

Homework Statement

On your first day at work for an appliance manufacturer, you are told to figure out what to do to the period of rotation during a washer spin cycle to triple the centripetal acceleration. You impress your boss by answering immediately.

Express your answer in terms of T.

Homework Equations

a=(4pi^2R)/T^2

The Attempt at a Solution

I read the question, and I keep thinking they just want to triple the accleration...which is not the answer. I don't exactly know what they are asking for...

 

[Kurdt]

Using that equation is a bit nasty since T is squared. You can tidy it up by remembering that R=v^2/a. So once you have your equation You pretty much have your answer since you know how the two quantities are related. When one triples the other _______.

 

[CursedAntagonis]

Using that equation is a bit nasty since T is squared. You can tidy it up by remembering that R=v^2/a. So once you have your equation You pretty much have your answer since you know how the two quantities are related. When one triples the other _______.

This is part of an online homework and the program keeps telling me I am getting the wrong answer.

It wants the answer in terms of T and I cannot have variables a, v, R or pi in there. I must be making an exteremely dumb mistake...

 

[Kurdt]

If I said a was proportional to the inverse of T, that is:

a \propto \frac{1}{T}

The you you want 3 x a, what will the above proportionality be? That is what would be done to T to make a 3 times larger?

 

[Kurdt]

bump

Why have you bumped this thread?

 

[treverd]

Help with answer!

So does anyone have an idea what the answer is?

I have this same question and for the answer they have it setup as

T^3=_____________

Thanks

 

[Kurdt]

We don't provide the answers for you here. You have to show some of your own work.

 

[blindside]

Try an algebraic approach if you can't get it by thinking about it.

3a = 3\left[\frac{4\pi^2R}{T^2}\right]

Now get rid of the 3 on the RHS by determining a coefficient for T within the square.

 

[treverd]

Thank you BlindSide Youve been a great help.