Centroid of a bounded region: Help

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    Bounded Centroid
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SUMMARY

The discussion focuses on finding the centroid of the region bounded by the curves y = sqrt(x) and y = (1/2) * x. The area A is calculated using the integral A = [f(x) - g(x)]dx from x = 0 to x = 4, yielding A = ((2x^3)/3) - ((x^2)/4) evaluated from 0 to 4. A participant points out an error in the integration process, specifically regarding the integration of x^(1/2), which does not yield x^3. Correct integration techniques are crucial for accurate centroid calculations.

PREREQUISITES
  • Understanding of integral calculus, specifically definite integrals.
  • Familiarity with the concept of centroids in geometry.
  • Knowledge of the functions y = sqrt(x) and y = (1/2) * x.
  • Ability to perform algebraic manipulation of polynomial expressions.
NEXT STEPS
  • Review the process of finding centroids using integrals in calculus.
  • Practice integrating functions of the form x^(n) to solidify understanding of integration rules.
  • Explore applications of centroids in physics and engineering for real-world relevance.
  • Learn about numerical methods for approximating integrals when analytical solutions are complex.
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Students studying calculus, educators teaching integral calculus, and anyone interested in geometric applications of integrals.

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Homework Statement


Find the centroid of the region bounded by the graphs of y = sqrt (x) and y = (1/2) * x


Homework Equations


A = [f(x)-g(x)]dx
from point a -> b


The Attempt at a Solution


x = [0,4] ; p(0,0) and p(4,2)

I am just checking on if I did the integral correctly.

A = ((2x^3)/3) - ((x^2)/4)] 0 -> 4
 
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x31fighter said:

Homework Statement


Find the centroid of the region bounded by the graphs of y = sqrt (x) and y = (1/2) * x


Homework Equations


A = [f(x)-g(x)]dx
from point a -> b


The Attempt at a Solution


x = [0,4] ; p(0,0) and p(4,2)

I am just checking on if I did the integral correctly.

A = ((2x^3)/3) - ((x^2)/4)] 0 -> 4

Not quite. If you integrate x1/2 you don't get x3.
 

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