Centroid of solid enclosed by surface z= y^2 , plane x=0 ,

chetzread
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Homework Statement


Find the centroid of solid enclosed by surface z= y^2 , plane x=0 , x = 1 and z =1 . The density is 1

Homework Equations

The Attempt at a Solution


Here's my working .

Centoird = mass of inertia / mass
So , i find the mass first .

It's clear that the circle is on zx plane ... I am not sure whether to use z= rcos theta or z = rsin theta . Can you help ?
 

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chetzread said:

Homework Statement


Find the centroid of solid enclosed by surface z= y^2 , plane x=0 , x = 1 and z =1 . The density is 1

Homework Equations

The Attempt at a Solution


Here's my working .

Centoird = mass of inertia / mass
So , i find the mass first .

It's clear that the circle is on zx plane ... I am not sure whether to use z= rcos theta or z = rsin theta . Can you help ?
Almost everything you have here is wrong.
  • Your drawing is way off. Take more time and get a more careful drawing the represents the solid described in your problem statement.
  • "the circle is on zx plane" -- No, it's not a circle.
  • You are apparently trying to use polar coordinates -- why?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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