hamsterman
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I'm trying to find \frac{1}{2\pi}\int \limits_{-\infty}^{\infty}e^{-itx}\frac{1}{a^2+x^2}\mathrm{d}x where 'a' is a constant.
First I noticed that there is \frac {\partial \arctan x}{\partial x} in this and using a substitute got \int \limits_0^{\pi / 2}\cos( t \tan x )\mathrm{d}x with some constants in the gaps.
I then remember that I'm working in complex numbers, factored a^2+x^2 and got something essentially along the lines of \int \frac{e^x}{x}\mathrm{d}x, or maybe rather \int \limits_0^{\infty} \frac {\cos tx} {a - ix}\mathrm{d}x.
I can't integrate either.
First I noticed that there is \frac {\partial \arctan x}{\partial x} in this and using a substitute got \int \limits_0^{\pi / 2}\cos( t \tan x )\mathrm{d}x with some constants in the gaps.
I then remember that I'm working in complex numbers, factored a^2+x^2 and got something essentially along the lines of \int \frac{e^x}{x}\mathrm{d}x, or maybe rather \int \limits_0^{\infty} \frac {\cos tx} {a - ix}\mathrm{d}x.
I can't integrate either.
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