Change in total energy of capacitance

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SUMMARY

When an initially charged capacitor is connected to an uncharged capacitor, the total energy of the system decreases due to energy dissipation in the circuit. This energy loss occurs primarily as heat in the resistance of the wires and the capacitors themselves. Additionally, if a spark is produced during the connection, energy is radiated away as electromagnetic radiation. The discussion emphasizes that under ideal conditions with zero resistance, energy conservation can be maintained through oscillations between the capacitors.

PREREQUISITES
  • Understanding of capacitor theory, specifically series and parallel configurations.
  • Familiarity with Kirchhoff's laws and their application in circuit analysis.
  • Knowledge of energy conservation principles in electrical systems.
  • Basic concepts of heat dissipation and electromagnetic radiation in circuits.
NEXT STEPS
  • Study the principles of energy dissipation in resistive circuits.
  • Learn about the behavior of capacitors in series and parallel configurations.
  • Explore the effects of inductance in circuits with oscillating currents.
  • Investigate the conditions under which energy conservation holds in electrical systems, particularly in cryogenic environments.
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Students of electrical engineering, physics enthusiasts, and anyone interested in understanding energy dynamics in capacitor circuits.

roxanne.w
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Homework Statement


When an initially charged capacitor is connected in a circuit with an uncharged capacitor, why would the total energy of both capacitors be less than the initial energy of the charged capacitor?

Homework Equations


This was a question asking for an explanation, so I'm not sure if any equations are relevant here.
1/C = 1/C1 + 1/C2

The Attempt at a Solution


Would it be due to heat dissipated in the circuit when the charge (or current?) flows in the circuit? Also, the suggested explanation was that a spark was produced - why and where this happens, I don't really know.

Thanks for your help!
 
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Hi roxanne.w, welcome to PF. :smile:

You have used conservation of charge to prove that the total energy after they are connected is less? Yes, the explanation is that energy is lost in resistance, that of the wire and of the foil comprising the capacitor. Energy from the spark radiates into space as light and other EM radiation.
 
roxanne.w said:

Homework Statement


When an initially charged capacitor is connected in a circuit with an uncharged capacitor, why would the total energy of both capacitors be less than the initial energy of the charged capacitor?

Homework Equations


This was a question asking for an explanation, so I'm not sure if any equations are relevant here.
1/C = 1/C1 + 1/C2

The Attempt at a Solution


Would it be due to heat dissipated in the circuit when the charge (or current?) flows in the circuit? Also, the suggested explanation was that a spark was produced - why and where this happens, I don't really know.

Thanks for your help!
You have assumed Kirchhoff's laws in determining before-and-after energies. Therefore, radiation is excluded as a mechanism for explaining energy loss.

The correct answer is heat dissipation or, if we assume zero resistance, which is theoretically possible in a cryogenic environment, finite inductance resulting in non-decaying current oscillations, with the charges moving back and forth between capacitors. In this latter case there is indeed conservation of energy, the sum of capacitive and inductive energies at any instant being constant = 1/2 Cv2(0+) if we assume one capacitor C had all the original charge Q = Cv(0+).
.
 

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