Change in total energy of capacitance

In summary, when an initially charged capacitor is connected in a circuit with an uncharged capacitor, the total energy of both capacitors is less than the initial energy of the charged capacitor due to heat dissipation in the circuit or, in the case of zero resistance, finite inductance resulting in non-decaying current oscillations. This results in conservation of energy, with the sum of capacitive and inductive energies remaining constant.
  • #1
roxanne.w
2
0

Homework Statement


When an initially charged capacitor is connected in a circuit with an uncharged capacitor, why would the total energy of both capacitors be less than the initial energy of the charged capacitor?

Homework Equations


This was a question asking for an explanation, so I'm not sure if any equations are relevant here.
1/C = 1/C1 + 1/C2

The Attempt at a Solution


Would it be due to heat dissipated in the circuit when the charge (or current?) flows in the circuit? Also, the suggested explanation was that a spark was produced - why and where this happens, I don't really know.

Thanks for your help!
 
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  • #2
Hi roxanne.w, welcome to PF. :smile:

You have used conservation of charge to prove that the total energy after they are connected is less? Yes, the explanation is that energy is lost in resistance, that of the wire and of the foil comprising the capacitor. Energy from the spark radiates into space as light and other EM radiation.
 
  • #3
roxanne.w said:

Homework Statement


When an initially charged capacitor is connected in a circuit with an uncharged capacitor, why would the total energy of both capacitors be less than the initial energy of the charged capacitor?

Homework Equations


This was a question asking for an explanation, so I'm not sure if any equations are relevant here.
1/C = 1/C1 + 1/C2

The Attempt at a Solution


Would it be due to heat dissipated in the circuit when the charge (or current?) flows in the circuit? Also, the suggested explanation was that a spark was produced - why and where this happens, I don't really know.

Thanks for your help!
You have assumed Kirchhoff's laws in determining before-and-after energies. Therefore, radiation is excluded as a mechanism for explaining energy loss.

The correct answer is heat dissipation or, if we assume zero resistance, which is theoretically possible in a cryogenic environment, finite inductance resulting in non-decaying current oscillations, with the charges moving back and forth between capacitors. In this latter case there is indeed conservation of energy, the sum of capacitive and inductive energies at any instant being constant = 1/2 Cv2(0+) if we assume one capacitor C had all the original charge Q = Cv(0+).
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FAQ: Change in total energy of capacitance

What is total energy of capacitance?

Total energy of capacitance refers to the amount of energy stored in a capacitor. It is the result of the electric charge and the voltage across the capacitor.

How is the total energy of capacitance calculated?

The total energy of capacitance can be calculated using the formula: E = (1/2)CV^2, where E is the energy in joules, C is the capacitance in farads, and V is the voltage in volts.

What factors affect the change in total energy of capacitance?

The change in total energy of capacitance is affected by the capacitance value, the voltage across the capacitor, and the amount of charge stored in the capacitor. Additionally, the type of dielectric material used in the capacitor can also affect the total energy of capacitance.

How does changing the capacitance value affect the total energy of capacitance?

Increasing the capacitance value will increase the total energy of capacitance, as the capacitor is able to store more charge at a given voltage. Conversely, decreasing the capacitance value will decrease the total energy of capacitance.

What is the significance of understanding the change in total energy of capacitance?

Understanding the change in total energy of capacitance is important in designing and using capacitors in electronic circuits. It allows for the calculation and control of the amount of energy stored in a capacitor, which can impact the performance and stability of the circuit.

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