# Changing pitch in frequency ratio?

v=fΛ

v=√(T/μ)

## The Attempt at a Solution

I know I'm supposed to make an attempt, but I can make heads nor tails of this. Are they changed in a constant ratioo? Does the tension come into play?

Last edited:

berkeman
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## Homework Statement

View attachment 771

What's weird too is that they are saying the frequency goes down, but decreasing string length should make the frequency go up...

haruspex
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What's weird too is that they are saying the frequency goes down, but decreasing string length should make the frequency go up...
Well, it says the ratio 4/5, which maybe should be read 4:5. It doesn't say "to 4/5".
Mickey, tension doesn't come into it because the tension isn't changing. You quote two equations, one of which is relevant, and gives the right answer.

Mickey Tee
Ohh, the only way I was picturing it was the strings being slackened or maybe a reversal of elastic elongation. :P Too much thought into a simple question.

haruspex
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Ohh, the only way I was picturing it was the strings being slackened or maybe a reversal of elastic elongation. :P Too much thought into a simple question.
Okay! Yes, it's annoying when you get locked into a misreading like that.

Thanks!

And by the way, a very happy new year to you haru! :D
May it bring you many new experiences.

onkar0027
For strings the frequency is given by
f=1/2L sqroot(t/m)

Now f is inversely proportional to length of string

Use this relation to find the answer