Charge between two metal plates

AI Thread Summary
The discussion centers on calculating the charge |q| between two large metal plates with an area of 1.1 m^2, separated by 6.2 cm, and an electric field magnitude of 50 N/C. The relevant equations include |q|=σA and E=σ/(2Eo), leading to the formula |q|=2EoEA. The calculated charge was found to be approximately 9.889E-7 C. However, it was noted that there was confusion regarding the use of Coulomb's constant instead of the permittivity of free space in the calculations. The thread emphasizes the importance of correctly applying the constants in electrostatic equations.
Jrlinton
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Homework Statement


Two large metal plates of area 1.1 m^2 face each other, 6.2 cm apart, with equal charge magnitudes but opposite signs. The field magnitude E between them (neglect fringing) is 50 N/C. Find |q|.

Homework Equations


|q|=σA
E=σ/(2Eo)⇒σ=2EoE
|q|=2EoEA

The Attempt at a Solution


I thought that after I did the rearranging of formulas above that this would be a pretty simple problem
|q|=2EoEA
|q|=2(8.99E-9C)(50N/C)(1.1m^2)
|q|=9.889E-7C
 
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Jrlinton said:

Homework Statement


Two large metal plates of area 1.1 m^2 face each other, 6.2 cm apart, with equal charge magnitudes but opposite signs. The field magnitude E between them (neglect fringing) is 50 N/C. Find |q|.

Homework Equations


|q|=σA
E=σ/(2Eo)⇒σ=2EoE
|q|=2EoEA

The Attempt at a Solution


I thought that after I did the rearranging of formulas above that this would be a pretty simple problem
|q|=2EoEA
|q|=2(8.99E-9C)(50N/C)(1.1m^2)
|q|=9.889E-7C
There are two plates.
 
It seems that I used coulombs constant instead of the permittivity of free space
 
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